A ray of light suffers minimum deviation when | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For a prism,the refractive index $\mu$ is given by the formula: $\mu = \frac{\sin((A + \delta_m)/2)}{\sin(A/2)}$.At the condition of minimum devia

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(C) For a prism,the refractive index $\mu$ is given by the formula: $\mu = \frac{\sin((A + \delta_m)/2)}{\sin(A/2)}$.At the condition of minimum deviation,the angle of incidence $i$ is equal to the angle of emergence $e$,and the angle of refraction $r_1 = r_2 = A/2$.Thus,the angle of incidence is given by $i = (A + \delta_m)/2$.Substituting this into the refractive index formula: $\mu = \frac{\sin i}{\sin(A/2)}$.Given $\mu = \sqrt{2}$ and $A = 60^{\circ}$,we have: $\sqrt{2} = \frac{\sin i}{\sin(60^{\circ}/2)}$.$\sqrt{2} = \frac{\sin i}{\sin 30^{\circ}}$.Since $\sin 30^{\circ} = 0.5$,we get: $\sin i = \sqrt{2} 	imes 0.5 = \frac{\sqrt{2}}{2} = \frac{1}{\sqrt{2}}$.Therefore,$i = \sin^{-1}(1/\sqrt{2}) = 45^{\circ}$.

$A$ ray of light suffers minimum deviation when incident on a $60^{\circ}$ prism of refractive index $\sqrt{2}$. The angle of incidence is......$^{\circ}$

Similar Questions

If the angle of prism is $60^o$ and the angle of minimum deviation is $40^o$,the angle of refraction will be.....$^o$

For flint and crown glass prisms,the prism angles are $A'$ and $A$ respectively. When they are used to produce dispersion without deviation,the ratio $A'/A$ will be:

$A$ light ray is incident on an equilateral glass prism placed on a horizontal table. Which of the following is true for the condition of minimum deviation?

When white light passes through a glass prism,one gets a spectrum on the other side of the prism. In the emergent beam,the ray which deviates the least is:

$A$ ray of light passing through an equilateral prism has a velocity of $2.12 \times 10^8 \text{ m/s}$ in the prism material. The minimum angle of deviation is . . . . . . degrees.

Vedclass Test Series

Exam Paper Generator

Online Exam Module